Optimal. Leaf size=137 \[ \frac{b \sin (e+f x) (d \sec (e+f x))^n \text{Hypergeometric2F1}\left (\frac{1}{2},-\frac{n}{2},\frac{2-n}{2},\cos ^2(e+f x)\right )}{f n \sqrt{\sin ^2(e+f x)}}-\frac{a d \sin (e+f x) (d \sec (e+f x))^{n-1} \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{1-n}{2},\frac{3-n}{2},\cos ^2(e+f x)\right )}{f (1-n) \sqrt{\sin ^2(e+f x)}} \]
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Rubi [A] time = 0.094441, antiderivative size = 137, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {3787, 3772, 2643} \[ \frac{b \sin (e+f x) (d \sec (e+f x))^n \, _2F_1\left (\frac{1}{2},-\frac{n}{2};\frac{2-n}{2};\cos ^2(e+f x)\right )}{f n \sqrt{\sin ^2(e+f x)}}-\frac{a d \sin (e+f x) (d \sec (e+f x))^{n-1} \, _2F_1\left (\frac{1}{2},\frac{1-n}{2};\frac{3-n}{2};\cos ^2(e+f x)\right )}{f (1-n) \sqrt{\sin ^2(e+f x)}} \]
Antiderivative was successfully verified.
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Rule 3787
Rule 3772
Rule 2643
Rubi steps
\begin{align*} \int (d \sec (e+f x))^n (a+b \sec (e+f x)) \, dx &=a \int (d \sec (e+f x))^n \, dx+\frac{b \int (d \sec (e+f x))^{1+n} \, dx}{d}\\ &=\left (a \left (\frac{\cos (e+f x)}{d}\right )^n (d \sec (e+f x))^n\right ) \int \left (\frac{\cos (e+f x)}{d}\right )^{-n} \, dx+\frac{\left (b \left (\frac{\cos (e+f x)}{d}\right )^n (d \sec (e+f x))^n\right ) \int \left (\frac{\cos (e+f x)}{d}\right )^{-1-n} \, dx}{d}\\ &=-\frac{a \cos (e+f x) \, _2F_1\left (\frac{1}{2},\frac{1-n}{2};\frac{3-n}{2};\cos ^2(e+f x)\right ) (d \sec (e+f x))^n \sin (e+f x)}{f (1-n) \sqrt{\sin ^2(e+f x)}}+\frac{b \, _2F_1\left (\frac{1}{2},-\frac{n}{2};\frac{2-n}{2};\cos ^2(e+f x)\right ) (d \sec (e+f x))^n \sin (e+f x)}{f n \sqrt{\sin ^2(e+f x)}}\\ \end{align*}
Mathematica [A] time = 0.148842, size = 107, normalized size = 0.78 \[ \frac{\sqrt{-\tan ^2(e+f x)} \csc (e+f x) (d \sec (e+f x))^n \left (a (n+1) \cos (e+f x) \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{n}{2},\frac{n+2}{2},\sec ^2(e+f x)\right )+b n \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{n+1}{2},\frac{n+3}{2},\sec ^2(e+f x)\right )\right )}{f n (n+1)} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.549, size = 0, normalized size = 0. \begin{align*} \int \left ( d\sec \left ( fx+e \right ) \right ) ^{n} \left ( a+b\sec \left ( fx+e \right ) \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \sec \left (f x + e\right ) + a\right )} \left (d \sec \left (f x + e\right )\right )^{n}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (b \sec \left (f x + e\right ) + a\right )} \left (d \sec \left (f x + e\right )\right )^{n}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (d \sec{\left (e + f x \right )}\right )^{n} \left (a + b \sec{\left (e + f x \right )}\right )\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \sec \left (f x + e\right ) + a\right )} \left (d \sec \left (f x + e\right )\right )^{n}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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